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Алгебра | Константин Чепуркин. Лекция 3

Лекция
Предмет:
Дата записи:
15.09.21
Дата публикации:
20.09.21
Код для блога:

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Аватар пользователя Viktor

1:40:00 Пусть 0=1 и a', a" два элемента из кольца, тогда из дистрибутивности следует 0(a'−a")=0 и a'−a"=1(a'−a")=0(a'−a")=0 ⇒ a'=a"=0=1. Докажем 0a=a0=0. a+0a=1a+0a=(1+0)a=1a=a ⇒ 0a=0, аналогично a0=0. Из последнего следует (−1)a=a(−1)=−a. a+(−1)a=1a+(−1)a=(1+(−1))a=0a=0.

Аватар пользователя thomasrichard

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Аватар пользователя ducklife12

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Аватар пользователя ducklife12

In dordle is a fantastic game to have on hand when you're feeling depressed, exhausted, or simply need a small reminder that life is wonderful!

Аватар пользователя babyball

This is a free game with the challenge of guessing a country by its flag over six attempts instead of guessing an English word. Flagle is now free here and you can play it on web browsers.

Аватар пользователя babyball

This is a free game with the challenge of guessing a country by its flag over six attempts instead of guessing an English word. Flagle is now free here and you can play it on web browsers.